周长 x^2-3x+4y+y^2=16

解答

周长

x^{2} - 3 x + 4 y + y^{2} = 16

C = 89 π

求解步骤

C = 2 π r

求出半径

给定

x^{2} - 3 x + 4 y + y^{2} = 16

的圆半径:

r = \frac{89}{2}

C = 2 π \frac{89}{2}

整理后得

C = 89 π

c i rc u m f ere n ce x^{2} + y^{2} + 4 x + 12 y + 3 = 0

c i rc u m f ere n ce x^{2} + y^{2} + 5 x + 20 y + 10 = 0

c i rc u m f ere n ce x^{2} + y^{2} - 4 x + 6 y + 4 = 0

c i rc l e, f in d C i rc u m f ere n ce, g i v e n r = 13

c i rc u m f ere n ce (x - 8)^{2} + (y - 8)^{2} = 16