6x^2-6x+3y^2+3y-102=0

Lösung

6 x^{2} - 6 x + 3 y^{2} + 3 y - 102 = 0

(h, k) = (\frac{1}{2}, - \frac{1}{2}), a = \frac{139}{2 2}, b = \frac{139}{2}

Schritte zur Lösung

6 x^{2} - 6 x + 3 y^{2} + 3 y - 102 = 0

Rewrite

6 x^{2} - 6 x + 3 y^{2} + 3 y - 102 = 0

in the form of the standard ellipse equation

\frac{( x - \frac{1}{2} ) ^{2}}{( \frac{139}{2 2} ) ^{2}} + \frac{( y - ( - \frac{1}{2} ) ) ^{2}}{( \frac{139}{2} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (\frac{1}{2}, - \frac{1}{2}), a = \frac{139}{2 2}, b = \frac{139}{2}

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (\frac{1}{2}, - \frac{1}{2}), b = \frac{139}{2}, a = \frac{139}{2 2}

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