(12(x-1)^2)/(24)+(3y^2)/(24)= 24/24

Lösung

\frac{12 ( x - 1 ) ^{2}}{24} + \frac{3 y ^{2}}{24} = \frac{24}{24}

(h, k) = (1, 0), a = 2, b = 22

Schritte zur Lösung

\frac{12 ( x - 1 ) ^{2}}{24} + \frac{3 y ^{2}}{24} = \frac{24}{24}

Rewrite

\frac{12 ( x - 1 ) ^{2}}{24} + \frac{3 y ^{2}}{24} = \frac{24}{24}

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{( 2 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 2 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, 0), a = 2, b = 22

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (1, 0), b = 22, a = 2

2 x^{2} + y^{2} = 57

\frac{( x - 3 ) ^{2}}{49} + \frac{( y - 5 ) ^{2}}{4} = 1

8 x^{2} + 2 y^{2} - 16 x - 16 y + 8 = 0

5 x^{2} + 2 y^{2} + 12 y + 8 = 0

y^{2} = 100 - 4 x^{2}