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Beliebt Geometry >

2x^2+y^2<= 8

Lösung

2 x^{2} + y^{2} \leq 8

Lösung

(h, k) = (0, 0), a = 2, b = 22

Schritte zur Lösung

2 x^{2} + y^{2} \leq 8

Rewrite

2 x^{2} + y^{2} \leq 8

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 2 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 22

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 22, a = 2

Graph

Beliebte Beispiele

x^2+4y^2-12x-16y=48

x^{2} + 4 y^{2} - 12 x - 16 y = 48

(x-3)^2+((y+3)/(16))^2=1

(x - 3)^{2} + (\frac{y + 3}{16})^{2} = 1

100x^2+4y^2+1200x-32y+3264=0

100 x^{2} + 4 y^{2} + 1200 x - 32 y + 3264 = 0

16x^2+15y^2-64x-90y-41=0

16 x^{2} + 15 y^{2} - 64 x - 90 y - 41 = 0

25y^2+9x^2-108x-200y+499=0

25 y^{2} + 9 x^{2} - 108 x - 200 y + 499 = 0