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Beliebt Geometry >

((x-5)^2)/9+((y+3)^2)/4 =1

Lösung

\frac{( x - 5 ) ^{2}}{9} + \frac{( y + 3 ) ^{2}}{4} = 1

Lösung

(h, k) = (5, - 3), a = 3, b = 2

Schritte zur Lösung

\frac{( x - 5 ) ^{2}}{9} + \frac{( y + 3 ) ^{2}}{4} = 1

Rewrite

\frac{( x - 5 ) ^{2}}{9} + \frac{( y + 3 ) ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - 5 ) ^{2}}{3 ^{2}} + \frac{( y - ( - 3 ) ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (5, - 3), a = 3, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (5, - 3), a = 3, b = 2

Graph

Beliebte Beispiele

(y^2)/(16)+(x^2)/(36)=1

\frac{y ^{2}}{16} + \frac{x ^{2}}{36} = 1

((x+2)^2)/(55)+((y-2)^2)/(64)=1

\frac{( x + 2 ) ^{2}}{55} + \frac{( y - 2 ) ^{2}}{64} = 1

((x+4)^2}{25}+\frac{(y+7)^2)/4 =1

\frac{( x + 4 ) ^{2}}{25} + \frac{( y + 7 ) ^{2}}{4} = 1

-8x^2-y^2-4x+5y+9=0

- 8 x^{2} - y^{2} - 4 x + 5 y + 9 = 0

(X/3)^2+(Y/2)^2=1

(\frac{X}{3})^{2} + (\frac{Y}{2})^{2} = 1