2y^2+20x+12y-1=0

Lösung

2 y^{2} + 20 x + 12 y - 1 = 0

(h, k) = (\frac{19}{20}, - 3), p = - \frac{5}{2}

Schritte zur Lösung

2 y^{2} + 20 x + 12 y - 1 = 0

Rewrite

2 y^{2} + 20 x + 12 y - 1 = 0

in the standard form

4 (- \frac{5}{2}) (x - \frac{19}{20}) = (y - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (\frac{19}{20}, - 3), p = - \frac{5}{2}

x = y^{2} - 3 y

- 4 y^{2} - 12 y + 1 = 3 x - 5

- y^{2} - 6 x = 0

2 x + y^{2} = 48

3 x^{2} + y = 4