foki x^2+4y^2+6x+16y+21=0

Lösung

foki

x^{2} + 4 y^{2} + 6 x + 16 y + 21 = 0

(- 3 + 3, - 2), (- 3 - 3, - 2)

Schritte zur Lösung

(h + c, k), (h - c, k)

Calculate ellipse properties

x^{2} + 4 y^{2} + 6 x + 16 y + 21 = 0 :

Ellipse with center

(h, k) = (- 3, - 2), a = 2, b = 1

(- 3 + c, - 2), (- 3 - c, - 2)

Compute

c :

c = 2^{2} - 1^{2} : 3

(- 3 + 3, - 2), (- 3 - 3, - 2)

f oc i \frac{( x + 1 ) ^{2}}{\frac{3}{2}} + \frac{y ^{2}}{1} = 1

f oc i 9 x^{2} + 4 y^{2} + 32 y + 28 = 0

f oc i \frac{x ^{2}}{625} + \frac{y ^{2}}{400} = 1

f oc i 4 x^{2} + 25 y^{2} + 40 x - 150 y + 225 = 0

f oc i \frac{x ^{2}}{\frac{81}{4}} + \frac{y ^{2}}{\frac{25}{16}} = 1