foki (x^2}{140}+\frac{(y-6)^2)/4 =1

Lösung

foki

\frac{x ^{2}}{140} + \frac{( y - 6 ) ^{2}}{4} = 1

(234, 6), (- 234, 6)

Schritte zur Lösung

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{140} + \frac{( y - 6 ) ^{2}}{4} = 1 :

Ellipse with center

(h, k) = (0, 6), a = 235, b = 2

(0 + c, 6), (0 - c, 6)

Compute

c :

c = (235)^{2} - 2^{2} : 234

(0 + 234, 6), (0 - 234, 6)

Fasse zusammen

(234, 6), (- 234, 6)

f oc i \frac{x ^{2}}{81} + \frac{y ^{2}}{4} = 1

f oc i \frac{x ^{2}}{100} + \frac{( y - 6 ) ^{2}}{64} = 1

f oc i \frac{( x - 1 ) ^{2}}{9} + \frac{( y + 2 ) ^{2}}{5} = 1

f oc i \frac{( x - 1 ) ^{2}}{9} + \frac{y ^{2}}{4} = 1

f oc i 4 x^{2} + 9 y^{2} + 16 x - 90 y + 205 = 0