center 9x^2+16y^2-72x+64y-368=0

Lösung

center

9 x^{2} + 16 y^{2} - 72 x + 64 y - 368 = 0

(4, - 2)

Schritte zur Lösung

9 x^{2} + 16 y^{2} - 72 x + 64 y - 368 = 0

Rewrite

9 x^{2} + 16 y^{2} - 72 x + 64 y - 368 = 0

in the form of the standard ellipse equation

\frac{( x - 4 ) ^{2}}{8 ^{2}} + \frac{( y - ( - 2 ) ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (4, - 2), a = 8, b = 6

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (4, - 2), a = 8, b = 6

And the center is:

(4, - 2)

ce n t er x^{2} + y^{2} - 4 y = 0

ce n t er \frac{( x - 5 ) ^{2}}{4} + \frac{( y + 3 ) ^{2}}{16} = 1

ce n t er 12 x^{2} + 20 y^{2} - 12 x + 40 y - 37 = 0

ce n t er 2 x^{2} + y^{2} + 12 x - 6 y + 26 = 0

ce n t er 25 x^{2} + 144 y^{2} = 900