exzentrizität (x^2)/9+(y^2)/(16)>1

Lösung

exzentrizität

\frac{x ^{2}}{9} + \frac{y ^{2}}{16} > 1

\frac{7}{4}

Dezimale

0.66143 \dots

Schritte zur Lösung

= \frac{b ^{2} - a ^{2}}{b}

Schreibe um

\frac{x ^{2}}{9} + \frac{y ^{2}}{16} = 1

Calculate ellipse properties

\frac{x ^{2}}{9} + \frac{y ^{2}}{16} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 4, a = 3

= \frac{4 ^{2} - 3 ^{2}}{4}

\frac{4 ^{2} - 3 ^{2}}{4} = \frac{7}{4}

= \frac{7}{4}

ecce n t r i c i t y \frac{x ^{2}}{64} + \frac{y ^{2}}{100} = 1

ecce n t r i c i t y \frac{x ^{2}}{100} + \frac{y ^{2}}{64} = 1

ecce n t r i c i t y 81 x^{2} - 1296 x + 16 y^{2} + 64 y = - 3952

ecce n t r i c i t y 3 x^{2} + y^{2} - 24 x + 39 = 0

ecce n t r i c i t y 9 x^{2} + 16 y^{2} = 144