exzentrizität 5x^2+7y^2=35

Lösung

exzentrizität

5 x^{2} + 7 y^{2} = 35

\frac{2}{7}

Dezimale

0.53452 \dots

Schritte zur Lösung

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

5 x^{2} + 7 y^{2} = 35 :

Ellipse with center

(h, k) = (0, 0), a = 7, b = 5

= \frac{( 7 ) ^{2} - ( 5 ) ^{2}}{7}

\frac{( 7 ) ^{2} - ( 5 ) ^{2}}{7} = \frac{2}{7}

= \frac{2}{7}

ecce n t r i c i t y 3 x^{2} + y^{2} + 18 x - 2 y - 8 = 0

ecce n t r i c i t y x^{2} + 4 y^{2} - 16 = 0

ecce n t r i c i t y 36 x^{2} + 9 y^{2} = 324

ecce n t r i c i t y \frac{x ^{2}}{3} + \frac{y ^{2}}{5} = 1

ecce n t r i c i t y \frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1