exzentrizität 12x^2+8y^2=96

Lösung

exzentrizität

12 x^{2} + 8 y^{2} = 96

\frac{1}{3}

Dezimale

0.57735 \dots

Schritte zur Lösung

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

12 x^{2} + 8 y^{2} = 96 :

Ellipse with center

(h, k) = (0, 0), b = 23, a = 22

= \frac{( 2 3 ) ^{2} - ( 2 2 ) ^{2}}{2 3}

\frac{( 2 3 ) ^{2} - ( 2 2 ) ^{2}}{2 3} = \frac{1}{3}

= \frac{1}{3}

ecce n t r i c i t y 14 x^{2} + 8 y^{2} = 112

ecce n t r i c i t y \frac{x ^{2}}{16} + \frac{y ^{2}}{80} = 1

ecce n t r i c i t y 2 x^{2} + y^{2} = 50

ecce n t r i c i t y 4 x^{2} + 3 y^{2} + 8 x - 24 y + 51 = 0

ecce n t r i c i t y \frac{x ^{2}}{25} + \frac{y ^{2}}{36} = 1