exzentrizität 18y^2+24y+12x^2-12x=1

Lösung

exzentrizität

18 y^{2} + 24 y + 12 x^{2} - 12 x = 1

\frac{1}{3}

Dezimale

0.57735 \dots

Schritte zur Lösung

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

18 y^{2} + 24 y + 12 x^{2} - 12 x = 1 :

Ellipse with center

(h, k) = (\frac{1}{2}, - \frac{2}{3}), a = 1, b = \frac{2}{3}

= \frac{1 ^{2} - ( \frac{2}{3} ) ^{2}}{1}

\frac{1 ^{2} - ( \frac{2}{3} ) ^{2}}{1} = \frac{1}{3}

= \frac{1}{3}

ecce n t r i c i t y 9 x^{2} + 4 y^{2} + 54 x - 8 y + 49 = 0

ecce n t r i c i t y (\frac{x}{8})^{2} + (\frac{y}{6})^{2} = 1

ecce n t r i c i t y 4 x^{2} + 9 y^{2} - 8 x - 32 = 0

ecce n t r i c i t y 9 x^{2} + 6 y^{2} = 54

ecce n t r i c i t y 3 x^{2} + 10 y^{2} = 30