exzentrizität x^2+2y^2=3

Lösung

exzentrizität

x^{2} + 2 y^{2} = 3

\frac{1}{2}

Dezimale

0.70710 \dots

Schritte zur Lösung

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

x^{2} + 2 y^{2} = 3 :

Ellipse with center

(h, k) = (0, 0), a = 3, b = \frac{3}{2}

= \frac{( 3 ) ^{2} - ( \frac{3}{2} ) ^{2}}{3}

\frac{( 3 ) ^{2} - ( \frac{3}{2} ) ^{2}}{3} = \frac{1}{2}

= \frac{1}{2}

ecce n t r i c i t y 4 x^{2} + 9 y^{2} = 144

ecce n t r i c i t y \frac{x ^{2}}{16} + \frac{y ^{2}}{81} = 1

ecce n t r i c i t y \frac{x ^{2}}{5} + \frac{y ^{2}}{8} = 1

ecce n t r i c i t y 18 x^{2} + 4 y^{2} - 72 x + 4 y + 37 = 0

ecce n t r i c i t y \frac{x ^{2}}{9} + y^{2} = 1