achse (x^2)/5+(y^2)/9 =1

Lösung

achse

\frac{x ^{2}}{5} + \frac{y ^{2}}{9} = 1

semi - major axis b = 3, semi - minor axis a = 5

Schritte zur Lösung

\frac{x ^{2}}{5} + \frac{y ^{2}}{9} = 1

Rewrite

\frac{x ^{2}}{5} + \frac{y ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 5 ) ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 5, b = 3

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 3, a = 5

a x i s 36 x^{2} + 5 y^{2} - 90 y - 495 = 0

a x i s x^{2} + 4 y^{2} = 46

a x i s 9 x^{2} + y^{2} = 9

a x i s \frac{( x - 5 ) ^{2}}{4} + \frac{( y + 3 ) ^{2}}{16} = 1

a x i s x^{2} + 2 y^{2} + 2 x - 8 y + 7 = 0