8x^2-4y^2+10x-6y-8=0

解

8 x^{2} - 4 y^{2} + 10 x - 6 y - 8 = 0

(h, k) = (- \frac{5}{8}, - \frac{3}{4}), a = \frac{71}{8}, b = \frac{71}{4 2}

解答ステップ

8 x^{2} - 4 y^{2} + 10 x - 6 y - 8 = 0

8 x^{2} - 4 y^{2} + 10 x - 6 y - 8 = 0

を標準的な双曲線のequationで書き換える

\frac{( x - ( - \frac{5}{8} ) ) ^{2}}{( \frac{71}{8} ) ^{2}} - \frac{( y - ( - \frac{3}{4} ) ) ^{2}}{( \frac{71}{4 2} ) ^{2}} = 1

ゆえに双曲線の特性は:

(h, k) = (- \frac{5}{8}, - \frac{3}{4}), a = \frac{71}{8}, b = \frac{71}{4 2}