16x^2-96x-y^2-2y+139=0

解

16 x^{2} - 96 x - y^{2} - 2 y + 139 = 0

(h, k) = (3, - 1), a = \frac{1}{2}, b = 2

解答ステップ

16 x^{2} - 96 x - y^{2} - 2 y + 139 = 0

16 x^{2} - 96 x - y^{2} - 2 y + 139 = 0

を標準的な双曲線のequationで書き換える

\frac{( x - 3 ) ^{2}}{( \frac{1}{2} ) ^{2}} - \frac{( y - ( - 1 ) ) ^{2}}{2 ^{2}} = 1

ゆえに双曲線の特性は:

(h, k) = (3, - 1), a = \frac{1}{2}, b = 2