3x^2+3y=6

Lösung

3 x^{2} + 3 y = 6

(h, k) = (0, 2), p = - \frac{1}{4}

Schritte zur Lösung

3 x^{2} + 3 y = 6

Rewrite

3 x^{2} + 3 y = 6

in the standard form:

4 (- \frac{1}{4}) (y - 2) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 2), p = - \frac{1}{4}

4 x^{2} + 15 y = 0

X^{2} - 6 Y = 0

(y - 0)^{2} = 8 (x - 1)

2 x^{2} - 50 y = 0

(y + 2)^{2} = - 8 (x + 3)