(4(y-1)^2)/9-(4(x-3)^2)/(27)=1

解

\frac{4 ( y - 1 ) ^{2}}{9} - \frac{4 ( x - 3 ) ^{2}}{27} = 1

(h, k) = (3, 1), a = \frac{3}{2}, b = \frac{3 3}{2}

解答ステップ

\frac{4 ( y - 1 ) ^{2}}{9} - \frac{4 ( x - 3 ) ^{2}}{27} = 1

\frac{4 ( y - 1 ) ^{2}}{9} - \frac{4 ( x - 3 ) ^{2}}{27} = 1

を標準的な双曲線のequationで書き換える

\frac{( y - 1 ) ^{2}}{( \frac{3}{2} ) ^{2}} - \frac{( x - 3 ) ^{2}}{( \frac{3 3}{2} ) ^{2}} = 1

ゆえに双曲線の特性は:

(h, k) = (3, 1), a = \frac{3}{2}, b = \frac{3 3}{2}