y^2-16x^2+64x-200=0

解答

y^{2} - 16 x^{2} + 64 x - 200 = 0

(h, k) = (2, 0), a = 234, b = \frac{17}{2}

求解步骤

y^{2} - 16 x^{2} + 64 x - 200 = 0

将

y^{2} - 16 x^{2} + 64 x - 200 = 0

改写为标准双曲线方程形式

\frac{( y - 0 ) ^{2}}{( 2 34 ) ^{2}} - \frac{( x - 2 ) ^{2}}{( \frac{17}{2} ) ^{2}} = 1

因此双曲线的性质为:

(h, k) = (2, 0), a = 234, b = \frac{17}{2}

4 x^{2} - 5 y^{2} - 24 y - 16 = 0

- 3 x^{2} + y^{2} - 12 = 0

y^{2} = 4 x^{2} + 3 x + 2

(\frac{( y + 1 ) ^{2}}{( 1 )}) - (\frac{( x + 1 ) ^{2}}{( 1 )}) = 1

\frac{v ^{2}}{2} = 2 s^{2} - 0.02