x-y=-3x^2+2y^2

解

x - y = - 3 x^{2} + 2 y^{2}

(h, k) = (- \frac{1}{6}, - \frac{1}{4}), a = \frac{1}{4 3}, b = \frac{1}{6 2}

解答ステップ

x - y = - 3 x^{2} + 2 y^{2}

x - y = - 3 x^{2} + 2 y^{2}

を標準的な双曲線のequationで書き換える

\frac{( y - ( - \frac{1}{4} ) ) ^{2}}{( \frac{1}{4 3} ) ^{2}} - \frac{( x - ( - \frac{1}{6} ) ) ^{2}}{( \frac{1}{6 2} ) ^{2}} = 1

ゆえに双曲線の特性は:

(h, k) = (- \frac{1}{6}, - \frac{1}{4}), a = \frac{1}{4 3}, b = \frac{1}{6 2}