de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Geometry >

-x^2+4x+3y^2-12y-4=0

Lösung

- x^{2} + 4 x + 3 y^{2} - 12 y - 4 = 0

Lösung

(h, k) = (2, 2), a = 2, b = 23

Schritte zur Lösung

- x^{2} + 4 x + 3 y^{2} - 12 y - 4 = 0

Rewrite

- x^{2} + 4 x + 3 y^{2} - 12 y - 4 = 0

in the form of a standard hyperbola equation

\frac{( y - 2 ) ^{2}}{2 ^{2}} - \frac{( x - 2 ) ^{2}}{( 2 3 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, 2), a = 2, b = 23

Graph

Beliebte Beispiele

16*(x^2-2x)-25(y^2-4y)=484

16 \cdot (x^{2} - 2 x) - 25 (y^{2} - 4 y) = 484

((x-2)^2)/(12)-((3y^2+y))/(12)=1

\frac{( x - 2 ) ^{2}}{12} - \frac{( 3 y ^{2} + y )}{12} = 1

2x-4x^2=-9y^2-21y-50

2 x - 4 x^{2} = - 9 y^{2} - 21 y - 50

((x+3)^2)/9-((y-1)^2)/4 =1

\frac{( x + 3 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{4} = 1

((K(x))/2)^2=4096+4096-128x+x^2

(\frac{K ( x )}{2})^{2} = 4096 + 4096 - 128 x + x^{2}