x^2+4x-24y-92=0

Lösung

x^{2} + 4 x - 24 y - 92 = 0

(h, k) = (- 2, - 4), p = 6

Schritte zur Lösung

x^{2} + 4 x - 24 y - 92 = 0

Rewrite

x^{2} + 4 x - 24 y - 92 = 0

in the standard form

4 \cdot 6 (y - (- 4)) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, - 4), p = 6

y \leq x^{2} - 1

y \leq x^{2} - 5

y - 7 x^{2} = 6

y^{2} - x - 1 = 0

- f (x) = x^{2} + x + 1