x^2+(y-4)2=1

Lösung

x^{2} + (y - 4) 2 = 1

(h, k) = (0, \frac{9}{2}), p = - \frac{1}{2}

Schritte zur Lösung

x^{2} + (y - 4) \cdot 2 = 1

Rewrite

x^{2} + (y - 4) \cdot 2 = 1

in the standard form:

4 (- \frac{1}{2}) (y - \frac{9}{2}) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, \frac{9}{2}), p = - \frac{1}{2}

4 x^{2} + y = 5

3 x^{2} + 2 y = 17

3 y^{2} + 4 x + 4 y - 14 = 0

y 2 y = 4 x + 10

x^{2} + 28 = - 6 y - 8 x