4y^2+3x-6y-12=0

Lösung

4 y^{2} + 3 x - 6 y - 12 = 0

(h, k) = (\frac{19}{4}, \frac{3}{4}), p = - \frac{3}{16}

Schritte zur Lösung

4 y^{2} + 3 x - 6 y - 12 = 0

Rewrite

4 y^{2} + 3 x - 6 y - 12 = 0

in the standard form

4 (- \frac{3}{16}) (x - \frac{19}{4}) = (y - \frac{3}{4})^{2}

Therefore parabola properties are:

(h, k) = (\frac{19}{4}, \frac{3}{4}), p = - \frac{3}{16}

y = - \frac{x}{y}

25 (x + 2)^{2} + y = (x - 7)^{2} - 81

- 2 x^{2} + 6 x - 2 y - 1 = 0

x = - 4 y^{2}

x^{2} = 24 (y - 8)