7x^2+4y-24=0

Lösung

7 x^{2} + 4 y - 24 = 0

(h, k) = (0, 6), p = - \frac{1}{7}

Schritte zur Lösung

7 x^{2} + 4 y - 24 = 0

Rewrite

7 x^{2} + 4 y - 24 = 0

in the standard form:

4 (- \frac{1}{7}) (y - 6) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 6), p = - \frac{1}{7}

(x - 4)^{2} = 4 (y + 2)

r 2 r = - 9 + 6 q

x = 5 y^{2} - 3

x - 8 = - \frac{1}{20} (y + 2)^{2}

x^{2} + 4 y - 4 x = 0