x(2cx)=2y

Lösung

x (2 c x) = 2 y

(h, k) = (0, 0), p = \frac{1}{4 c}

Schritte zur Lösung

x \cdot 2 c x = 2 y

Rewrite

x \cdot 2 c x = 2 y

in the standard form

4 \cdot \frac{1}{4 c} (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{4 c}

y^{2} + 6 y + 4 = 5 x

y = x f (x)

(y + 5)^{2} = - 2 (x - 9)

x = y^{2} + y + 1

y^{2} = 4 + x