x^2+(y-3)2=16

Lösung

x^{2} + (y - 3) 2 = 16

(h, k) = (0, 11), p = - \frac{1}{2}

Schritte zur Lösung

x^{2} + (y - 3) \cdot 2 = 16

Rewrite

x^{2} + (y - 3) \cdot 2 = 16

in the standard form:

4 (- \frac{1}{2}) (y - 11) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 11), p = - \frac{1}{2}

x + (y - 1)^{2} = 1

x - 2 y^{2} - 12 y - 13 = 0

2 x^{2} - 2 y = 0

y = 2 x^{2} + 16 x + 29

x^{2} + 5 x = - y + 6