2x+5y^2=0

Lösung

2 x + 5 y^{2} = 0

(h, k) = (0, 0), p = - \frac{1}{10}

Schritte zur Lösung

2 x + 5 y^{2} = 0

Rewrite

2 x + 5 y^{2} = 0

in the standard form:

4 (- \frac{1}{10}) (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - \frac{1}{10}

- 3 x - y^{2} = - 1

5 x^{2} - 18 y + 180 = 0

2 x^{2} + y = 75

(x - 5)^{2} = - 70 (y - 1)

g (x) (a + b) = x^{2} - 4