3y^2+4x-24y+44=0

Lösung

3 y^{2} + 4 x - 24 y + 44 = 0

(h, k) = (1, 4), p = - \frac{1}{3}

Schritte zur Lösung

3 y^{2} + 4 x - 24 y + 44 = 0

Rewrite

3 y^{2} + 4 x - 24 y + 44 = 0

in the standard form

4 (- \frac{1}{3}) (x - 1) = (y - 4)^{2}

Therefore parabola properties are:

(h, k) = (1, 4), p = - \frac{1}{3}

4 x^{2} + 2 y = 10

(y + 7)^{2} = 4 (x - 1)

x^{2} - y > 0

(y - 2)^{2} = 40 (x - 2)

- 2 y^{2} + x = 6