(-y)^2=x+16

Lösung

(- y)^{2} = x + 16

(h, k) = (- 16, 0), p = \frac{1}{4}

Schritte zur Lösung

(- y)^{2} = x + 16

Rewrite

(- y)^{2} = x + 16

in the standard form

4 \cdot \frac{1}{4} (x - (- 16)) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- 16, 0), p = \frac{1}{4}

x^{2} - 18 x + 24 y + 273 = 0

y + 2 = x^{2} + 8 x

\frac{2}{3} x \leq y^{2}

x^{2} = - \frac{4}{3} y

(Y - 4)^{2} = 12 (X - 1)