-5x^2+y=10

Lösung

- 5 x^{2} + y = 10

(h, k) = (0, 10), p = \frac{1}{20}

Schritte zur Lösung

- 5 x^{2} + y = 10

Rewrite

- 5 x^{2} + y = 10

in the standard form:

4 \cdot \frac{1}{20} (y - 10) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 10), p = \frac{1}{20}

y^{2} + 2 y + 8 x + 1 = 0

16 - z = y^{2}

(y + 2) = 4 (x + 1)^{2}

x^{2} = - 14 (y + 1)

3 x^{2} + 12 y = 0