4y=x^2+4x-12

Lösung

4 y = x^{2} + 4 x - 12

(h, k) = (- 2, - 4), p = 1

Schritte zur Lösung

4 y = x^{2} + 4 x - 12

Rewrite

4 y = x^{2} + 4 x - 12

in the standard form

4 \cdot 1 \cdot (y - (- 4)) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, - 4), p = 1

y < x^{2} - 12 x + 38

x^{2} - y = 25

4 x^{2} + 8 x + k (x) = 0

x = - 3 y^{2} + 15 y - 18

R (x) e = (x - 4)^{2}