2x^2-12x-11y+40=0

Lösung

2 x^{2} - 12 x - 11 y + 40 = 0

(h, k) = (3, 2), p = \frac{11}{8}

Schritte zur Lösung

2 x^{2} - 12 x - 11 y + 40 = 0

Rewrite

2 x^{2} - 12 x - 11 y + 40 = 0

in the standard form

4 \cdot \frac{11}{8} (y - 2) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, 2), p = \frac{11}{8}

3 y^{2} - x = 9

y^{2} + x - 49 = 0

9 x^{2} + 24 x + 72 y - 20 = 0

x = y^{2} - 5 y + 6

4 x^{2} = 2 y