0=x^2+4x-4y+8

Lösung

0 = x^{2} + 4 x - 4 y + 8

(h, k) = (- 2, 1), p = 1

Schritte zur Lösung

0 = x^{2} + 4 x - 4 y + 8

Rewrite

0 = x^{2} + 4 x - 4 y + 8

in the standard form

4 \cdot 1 \cdot (y - 1) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, 1), p = 1

(y - (- 12))^{2} = 2 (x - 1)

y^{2} - x < 100

x^{2} + 2 y - 18 = 0

(y - 0)^{2} = 8 (x + 1)

2 x^{2} + 5 y = 0