x^2+10x-12y+13=0

Lösung

x^{2} + 10 x - 12 y + 13 = 0

(h, k) = (- 5, - 1), p = 3

Schritte zur Lösung

x^{2} + 10 x - 12 y + 13 = 0

Rewrite

x^{2} + 10 x - 12 y + 13 = 0

in the standard form

4 \cdot 3 (y - (- 1)) = (x - (- 5))^{2}

Therefore parabola properties are:

(h, k) = (- 5, - 1), p = 3

f (x) = \frac{2}{3} (x + 3) (x - 1)

y^{2} - 4 x + 8 y - 4 = 0

x^{2} - x \geq o

x^{2} + 2 y = 8

x^{2} = y + 6