y^2+12y-3x+27=0

Lösung

y^{2} + 12 y - 3 x + 27 = 0

(h, k) = (- 3, - 6), p = \frac{3}{4}

Schritte zur Lösung

y^{2} + 12 y - 3 x + 27 = 0

Rewrite

y^{2} + 12 y - 3 x + 27 = 0

in the standard form

4 \cdot \frac{3}{4} (x - (- 3)) = (y - (- 6))^{2}

Therefore parabola properties are:

(h, k) = (- 3, - 6), p = \frac{3}{4}

4 x^{2} - 4 y = - 12

(y + 5)^{2} = 3 (x - 3)

x^{2} + 2 x + y = 0

[1.6] g (x) = 2 x^{2} - x

D^{2} y - y = 5 + x^{2}