2x^2-5x+7y-9=0

Lösung

2 x^{2} - 5 x + 7 y - 9 = 0

(h, k) = (\frac{5}{4}, \frac{97}{56}), p = - \frac{7}{8}

Schritte zur Lösung

2 x^{2} - 5 x + 7 y - 9 = 0

Rewrite

2 x^{2} - 5 x + 7 y - 9 = 0

in the standard form

4 (- \frac{7}{8}) (y - \frac{97}{56}) = (x - \frac{5}{4})^{2}

Therefore parabola properties are:

(h, k) = (\frac{5}{4}, \frac{97}{56}), p = - \frac{7}{8}

y - y^{2} = x

(y + 1)^{2} = 4 (x + 3)

4 x^{2} + x + m (x) = 0

(x + 5)^{2} = 8 (y + 7)

3 X^{2} - 9 X - 2 = 5 Y