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Beliebt Geometry >

2x^2+4x+3y+14=0

Lösung

2 x^{2} + 4 x + 3 y + 14 = 0

Lösung

(h, k) = (- 1, - 4), p = - \frac{3}{8}

Schritte zur Lösung

2 x^{2} + 4 x + 3 y + 14 = 0

Rewrite

2 x^{2} + 4 x + 3 y + 14 = 0

in the standard form

4 (- \frac{3}{8}) (y - (- 4)) = (x - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - 4), p = - \frac{3}{8}

Graph

Beliebte Beispiele

y = 6 (x + 4)^{2} + 4

(x-5)^2=-16(y-1)

(x - 5)^{2} = - 16 (y - 1)

x^{2} - 8 x + y = 0

(x+5)^2=50(y+9)

(x + 5)^{2} = 50 (y + 9)

\frac{x ^{2}}{4} = 28 y