2y^2+x+6=8y

Lösung

2 y^{2} + x + 6 = 8 y

(h, k) = (2, 2), p = - \frac{1}{8}

Schritte zur Lösung

2 y^{2} + x + 6 = 8 y

Rewrite

2 y^{2} + x + 6 = 8 y

in the standard form

4 (- \frac{1}{8}) (x - 2) = (y - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, 2), p = - \frac{1}{8}

x + y^{2} = 64

y \leq x^{2} - 6 x

y + 4 = (x - 1)^{2}

(x - 4)^{2} + y^{2} \geq x^{2} + y^{2}

2 x^{2} - 12 x + 28 y = 38