t^2-10r=-7

Lösung

t^{2} - 10 r = - 7

(h, k) = (0, \frac{7}{10}), p = \frac{5}{2}

Schritte zur Lösung

t^{2} - 10 r = - 7

Rewrite

t^{2} - 10 r = - 7

in the standard form:

4 \cdot \frac{5}{2} (r - \frac{7}{10}) = (t - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, \frac{7}{10}), p = \frac{5}{2}

x^{2} + 4 x - 8 y + 44 = 0

y > 2 x^{2} + 5

- 3 x^{2} + 6 y + 2 x = 6

x^{2} + (y - 1) 2 = 1

- f (x) = 3 x^{2} - 3 x - 4