x=y^2-2y+8

Lösung

x = y^{2} - 2 y + 8

(h, k) = (7, 1), p = \frac{1}{4}

Schritte zur Lösung

x = y^{2} - 2 y + 8

Rewrite

x = y^{2} - 2 y + 8

in the standard form

4 \cdot \frac{1}{4} (x - 7) = (y - 1)^{2}

Therefore parabola properties are:

(h, k) = (7, 1), p = \frac{1}{4}

y^{2} + 4 = x

x = y^{2} - 2 y + 2

(x - 3) - y^{2} = 3

2 x^{2} - 6 x + P (x) = 0

2 y^{2} + 12 y + 2 x - 4 = 0