6x+4(y-2)^2=20

Lösung

6 x + 4 (y - 2)^{2} = 20

(h, k) = (\frac{10}{3}, 2), p = - \frac{3}{8}

Schritte zur Lösung

6 x + 4 (y - 2)^{2} = 20

Rewrite

6 x + 4 (y - 2)^{2} = 20

in the standard form:

4 (- \frac{3}{8}) (x - \frac{10}{3}) = (y - 2)^{2}

Therefore parabola properties are:

(h, k) = (\frac{10}{3}, 2), p = - \frac{3}{8}

x^{2} = - y + 3

3 f (x) = x^{2} - 4

y^{2} - 10 x = 0

(x + 3)^{2} = 12 (y + 2)

x = - 4 y^{2} + 16 y - 12