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Beliebt Geometry >

16y^2-x>0

Lösung

16 y^{2} - x > 0

Lösung

(h, k) = (0, 0), p = \frac{1}{64}

Schritte zur Lösung

16 y^{2} - x > 0

Rewrite

16 y^{2} - x > 0

in the standard form:

4 \cdot \frac{1}{64} (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{64}

Graph

Beliebte Beispiele

(x-7)^2=-6(y+7)

(x - 7)^{2} = - 6 (y + 7)

-8(x-5)=(y-4)^2

- 8 (x - 5) = (y - 4)^{2}

2*0.25piX*0.25pi=2pir^2*0.25pi

2 \cdot 0.25 π X \cdot 0.25 π = 2 π r^{2} \cdot 0.25 π

12 x^{2} + 25 y = 300

x^{2} - m (x) - 1 = 0