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Beliebt Geometry >

0>= 0.1x^2-200q(x)+19000

Lösung

0 \geq 0.1 x^{2} - 200 q (x) + 19000

Lösung

(h, k) = (0, 95), p = 500

Schritte zur Lösung

0 \geq 0.1 x^{2} - 200 y + 19000

Rewrite

0 \geq 0.1 x^{2} - 200 y + 19000

in the standard form:

4 \cdot 500 (y - 95) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 95), p = 500

Graph

Beliebte Beispiele

(x-2)^2=-6(y-1)

(x - 2)^{2} = - 6 (y - 1)

y^2-8y-12x+76=0

y^{2} - 8 y - 12 x + 76 = 0

x=-1/16 (y-2)^2-3

x = - \frac{1}{16} (y - 2)^{2} - 3

x^{2} - 6 x + 2 y - 8 = 0

x^{2} - 4 x - 5 y + 7 = 0