(x+2)^2+(y-4)^2=25

Lösung

(x + 2)^{2} + (y - 4)^{2} = 25

(a, b) = (- 2, 4), r = 5

Schritte zur Lösung

(x + 2)^{2} + (y - 4)^{2} = 25

Rewrite

(x + 2)^{2} + (y - 4)^{2} = 25

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 4)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 2, 4), r = 5

v er t i ces 9 x^{2} - 4 y^{2} - 72 x = 0

v er t i ces \frac{x ^{2}}{36} - \frac{y ^{2}}{64} = 1

9 x^{2} - 16 y^{2} = 144

2 x^{2} + 2 y^{2} - 12 x + 8 y - 24 = 0

f oc i \frac{( x - 5 ) ^{2}}{25} + \frac{( y + 3 ) ^{2}}{9} = 1