foki (3x-4)(4x-3)-2x

Lösung

foki

(3 x - 4) (4 x - 3) - 2 x

(\frac{9}{8}, - \frac{19}{6})

Schritte zur Lösung

Rewrite

y = (3 x - 4) (4 x - 3) - 2 x

in the standard form

4 \cdot \frac{1}{48} (y - (- \frac{51}{16})) = (x - \frac{9}{8})^{2}

(h, k) = (\frac{9}{8}, - \frac{51}{16}), p = \frac{1}{48}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(\frac{9}{8}, - \frac{51}{16})

along the y-axis

(\frac{9}{8}, - \frac{51}{16} + p)

= (\frac{9}{8}, - \frac{51}{16} + \frac{1}{48})

Fasse zusammen

(\frac{9}{8}, - \frac{19}{6})

f oc i 0.5 x^{2} - 2 x - 2

f oc i y = 2 x^{2} - 39

f oc i y^{2} + 6 y + 8 x + 25 = 0

f oc i \frac{x ^{5} + x ^{4} + x ^{3} + x ^{2} + x + 1}{x ^{3} + 1}

f oc i y^{2} - 12 y + 4 x + 4 = 0