de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Geometry >

foki y=4x^2+12x+3

Lösung

foki

y = 4 x^{2} + 12 x + 3

Lösung

(- \frac{3}{2}, - \frac{95}{16})

Schritte zur Lösung

Rewrite

y = 4 x^{2} + 12 x + 3

in the standard form

4 \cdot \frac{1}{16} (y - (- 6)) = (x - (- \frac{3}{2}))^{2}

(h, k) = (- \frac{3}{2}, - 6), p = \frac{1}{16}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- \frac{3}{2}, - 6)

along the y-axis

(- \frac{3}{2}, - 6 + p)

= (- \frac{3}{2}, - 6 + \frac{1}{16})

Fasse zusammen

(- \frac{3}{2}, - \frac{95}{16})

Graph

Beliebte Beispiele

f oc i y^{2} = x

foki y=3x^2-12x+8

f oc i y = 3 x^{2} - 12 x + 8

foki x^2-6x+5y=34

f oc i x^{2} - 6 x + 5 y = 34

foki y=2x(x-9)-(x-9)

f oc i y = 2 x (x - 9) - (x - 9)

foki-0.0000848x^2-0.006005x+1.004

f oc i - 0.0000848 x^{2} - 0.006005 x + 1.004