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Beliebt Geometry >

foki 2y=3x^2+x

Lösung

foki

2 y = 3 x^{2} + x

Lösung

(- \frac{1}{6}, \frac{1}{8})

Schritte zur Lösung

Rewrite

2 y = 3 x^{2} + x

in the standard form

4 \cdot \frac{1}{6} (y - (- \frac{1}{24})) = (x - (- \frac{1}{6}))^{2}

(h, k) = (- \frac{1}{6}, - \frac{1}{24}), p = \frac{1}{6}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- \frac{1}{6}, - \frac{1}{24})

along the y-axis

(- \frac{1}{6}, - \frac{1}{24} + p)

= (- \frac{1}{6}, - \frac{1}{24} + \frac{1}{6})

Fasse zusammen

(- \frac{1}{6}, \frac{1}{8})

Graph

Beliebte Beispiele

foki 2x^2+4x-y=0

f oc i 2 x^{2} + 4 x - y = 0

foki x=-1/52 (y^2+18y-647)

f oc i x = - \frac{1}{52} (y^{2} + 18 y - 647)

f oc i 4 x^{2} + 8 x

foki x^2-13x+40

f oc i x^{2} - 13 x + 40

foki-2x^2-8x-12

f oc i - 2 x^{2} - 8 x - 12