vértices x^2

{ "query": { "display": "vértices $$x^{2}$$", "symbolab_question": "CONIC#vertices x^{2}" }, "solution": { "level": "PERFORMED", "subject": "Geometry", "topic": "Parabola", "subTopic": "vertices", "default": "\\mathrm{Mínimo}\\:(0,0)", "meta": { "showVerify": true } }, "methods": [ { "method": "Encontrar el vértice utilizando la forma polinómica", "query": { "display": "vértice de la función cuadrática $$y=x^{2}$$", "symbolab_question": "vertexquadratic y=x^{2}" } }, { "method": "Encontrar el vértice utilizando la forma parábola", "query": { "display": "vértice de la parabola $$y=x^{2}$$", "symbolab_question": "vertexparabola y=x^{2}" } }, { "method": "Encontrar el vértice utilizando la forma canónica", "query": { "display": "forma del vértice $$y=x^{2}$$", "symbolab_question": "vertexform y=x^{2}" } }, { "method": "Encontrar el vértice con el promedio de los ceros", "query": { "display": "vertices cero $$y=x^{2}$$", "symbolab_question": "vertexzeros y=x^{2}" } } ], "steps": { "type": "interim", "title": "Vértice de la parábola dado $$y=x^{2}:{\\quad}$$Mínimo $$\\left(0,\\:0\\right)$$", "input": "y=x^{2}", "steps": [ { "type": "definition", "title": "Ecuación de parábola en forma polinómica", "text": "El vértice de una parábola abierta arriba abajo de la forma $$y=ax^2+bx+c\\:$$es $$x_{v}=-\\frac{b}{2a}$$" }, { "type": "step", "primary": "Los parámetros de la parábola son:", "result": "a=1,\\:b=0,\\:c=0" }, { "type": "step", "primary": "$$x_{v}=-\\frac{b}{2a}$$", "result": "x_{v}=-\\frac{0}{2\\cdot\\:1}" }, { "type": "step", "primary": "Simplificar", "result": "x_{v}=0" }, { "type": "interim", "title": "Ingresar $$x_{v}=0\\:$$para encontrar el valor $$y_{v}$$", "input": "y_{v}=0^{2}", "result": "y_{v}=0", "steps": [ { "type": "step", "primary": "Simplificar", "result": "y_{v}=0" } ], "meta": { "interimType": "Plug In Value 2Eq" } }, { "type": "step", "primary": "Por lo tanto, el vertice de la parabola es", "result": "\\left(0,\\:0\\right)" }, { "type": "step", "primary": "Si $$a<0,\\:$$entonces el vertice es un valor máximo<br/>Si $$a>0,\\:$$entonces el vertice es un valor minimo<br/>$$a=1$$", "result": "\\mathrm{Mínimo}\\:\\left(0,\\:0\\right)" } ], "meta": { "solvingClass": "Parabola" } }, "plot_output": { "meta": { "plotInfo": { "variable": "x", "funcsToDraw": { "funcs": [ { "evalFormula": "y=\\frac{x^{2}}{4\\frac{1}{4}}+0", "displayFormula": "4\\frac{1}{4}y=x^{2}", "attributes": { "color": "PURPLE", "lineType": "NORMAL", "isAsymptote": false } }, { "evalFormula": "y=-\\frac{1}{4}", "displayFormula": "y=-\\frac{1}{4}", "attributes": { "color": "GRAY", "lineType": "NORMAL", "labels": [ "\\mathrm{directrix}" ], "isAsymptote": false } } ] }, "pointsToDraw": { "pointsLatex": [ "(0,0)", "(0,\\frac{1}{4})" ], "pointsDecimal": [ { "fst": 0, "snd": 0 }, { "fst": 0, "snd": 0.25 } ], "attributes": [ { "color": "PURPLE", "labels": [ "\\mathrm{vertex}" ], "labelTypes": [ "DEFAULT" ], "labelColors": [ "PURPLE" ] }, { "color": "PURPLE", "labels": [ "\\mathrm{focus}" ], "labelTypes": [ "DEFAULT" ], "labelColors": [ "PURPLE" ] } ] }, "functionChanges": [ { "origFormulaLatex": [], "finalFormulaLatex": [], "plotTitle": "4\\cdot \\frac{1}{4}(y)=x^{2}", "paramsLatex": [], "paramsReplacementsLatex": [] } ], "localBoundingBox": { "xMin": -2.8125, "xMax": 2.8125, "yMin": -2.8125, "yMax": 2.8125 } }, "showViewLarger": true } }, "meta": { "showVerify": true } }